Understanding the Linearity Test for Inner Products

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SUMMARY

The function defined as <x,y> = x1x2 + y1y2 does not qualify as a valid inner product due to its failure to satisfy the linearity test. Specifically, when calculating <x+y,z>, it does not equal <x,z> + <y,z>, confirming its non-linearity. The confusion arose from misinterpreting the terms involved, particularly the roles of x1, x2, y1, and y2 in the inner product definition.

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Students and educators in mathematics, particularly those focusing on linear algebra and inner product spaces, will benefit from this discussion.

JamesGoh
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In one of my tutorial problems, I was asked to verify if the following function
is a valid inner product

<x,y>= x1x2 + y1y2

Note, x=(x1,x2)^{T} and y=(y1,y2)^{T}

where T means transpose of the matrix

The tutor said to us the answer is no because it fails the linearity test

Does it fail the linearity test because of the x1 and y1 terms in front of the x2 and y2 ?
 
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Try explicitly calculating
<br /> \langle x+y,z\rangle <br />
and see if it really does equal
<br /> \langle x,z\rangle +\langle y,z\rangle<br />
If it doesn't then you know it does not satisfy linearity.
 
Does <x,0*y>=0*<x,y>?
 
Yes, it does. But that doesn't prove anything.
 
HallsofIvy said:
Yes, it does.
No it doesn't. <x,0>=x1x2.
 
Oh, Blast! I was interpreting the given inner product wrong!
 

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