Question about integrating w/ specific time

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Lenjaku
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When I integrate v(t) after I calculated the t, what do I get?
Let;s say t=2.
do I get the position vector in this 2s?
If so it means the integral goes from 0 to t? or I still need to calculate from 2 to t?

I could simply integrate v from 0 to t then place 2 in the position vector but I got an ex here integrating after calculating the t...I knew I must not integrate vector after calculating the t since it won't be general anymore...but still there is a use for this it seems...
 
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I figure out I need to calculate 2 to t...