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Question about permutation cycles

  1. Dec 16, 2008 #1
    If A is a cycle, and A=(1 4 5) (2 3 6). Is there a B such that BAB^-1=A^2. I found
    A^2=(1 5 4) (2 6 3), but I'm not really sure where to go from there.
  2. jcsd
  3. Dec 16, 2008 #2


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    You know they are conjugate because they have the same cycle structure. If you need to find a B, then looking at your results, I'd say you want a B that reverses 5 and 4 and reverses 6 and 3. Can you think of one?
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