Question about reactions in biochemistry

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samy4408
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we assume that we have an exergonic reaction , a substrate going to a product , is the negative ΔG′° the principal reason that the equilibrium favors the product (there is more product than substrate at equilibrium )?, or it is not and that depends on other factors? , thanks .
 
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Given the relation between ΔG° and equilibrium, ΔG° = -RT ln K, anything that affects ΔG° also affects K and vice versa. They both contain the same information. It makes no sense to talk about equilibrium being determined by ΔG° and "other factors". Either you can say that ΔG° fully determines K, with no other factors involved, or you can say that both ΔG° and K (which are just different ways of saying the same thing) are fully determined by the "other factors". You can't mix the explanations, in a way that suggests that there can be factors that affect K but not ΔG°, or vice versa.
 
mjc123 said:
Given the relation between ΔG° and equilibrium, ΔG° = -RT ln K, anything that affects ΔG° also affects K and vice versa. They both contain the same information. It makes no sense to talk about equilibrium being determined by ΔG° and "other factors". Either you can say that ΔG° fully determines K, with no other factors involved, or you can say that both ΔG° and K (which are just different ways of saying the same thing) are fully determined by the "other factors". You can't mix the explanations, in a way that suggests that there can be factors that affect K but not ΔG°, or vice versa.
thanks a lot !