Question about resistors in Parallel

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SUMMARY

The discussion focuses on demonstrating that total resistance decreases when additional resistors are added to a parallel circuit. The formula used is R(Total) = 1/R(1) + 1/R(2) + ... + 1/R(n), with a specific example of 20 Ω resistors. Calculations show that for two resistors, the total resistance is 10 Ω, and for three resistors, it approximates to 6.7 Ω. The user seeks assistance in devising a practical experiment to validate this concept.

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Homework Statement


I need to devise an experiment to show that the total resistance decreases as additional resistors are added to a parallel circuit of resistors. All resistances of the resistors are the same.


Homework Equations


R(Total)=1/R(1)+1/R(2)+...+1/R(n)


The Attempt at a Solution


So far I can work it out mathematically say the resistance of the resistors is 20 Ω

For two resistors:
R(Total)=10 Ω
For three:
R(Total)≈6.7

So I can confirm that the total resistance of the circuit is increasing but I'm having problems devising the experiment.

Thanks in advance! :D
 
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