Question about series and sequences

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Homework Help Overview

The discussion revolves around the convergence or divergence of a sequence defined by the function a_{n}=\frac{2+3n}{2n+1} and the corresponding series formed by summing the terms of this sequence. Participants are exploring the implications of the divergence test and the relationship between the behavior of the sequence and the series.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the original poster's assertion that the sequence diverges and are examining the limit of the sequence as n approaches infinity. There is a discussion about the definitions of convergence and divergence in the context of sequences and series.

Discussion Status

The discussion is ongoing, with participants providing differing viewpoints on the convergence of the sequence and its implications for the series. Some participants are offering clarifications on the definitions involved, while others are questioning assumptions made about the behavior of the sequence.

Contextual Notes

There is a mention of potential confusion between the divergence of a sequence and the divergence of a series, as well as the importance of the limit approaching zero for series convergence. Participants are also reflecting on their understanding of these concepts based on prior learning.

warfreak131
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Homework Statement



I have a function [tex]a_{n}=\frac{2+3n}{2n+1}[/tex], and I have to find out whether it converges or diverges. I did the ratio test [tex]lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|[/tex]. And according to the divergence test, it should diverge. Then it asks if the series, (summation of [tex]a_n[/tex]) converges or diverges.

Now my question is, if a sequence diverges, does the series converge as well?
 
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Why do you say the sequence diverges?

[tex]a_{n}=\frac{2+3n}{2n+1} =\frac{3}{2} + \frac{1}{4n+2}[/tex]

Clearly converges. As to the series, you can see that every term is at least 3/2.
 
The divergence test says that if the limit of a function is not 0, then it diverges. And the limit is 3/2, which is not 0, so it diverges... right?
 
I was under the impression that a function/sequence diverges if the limit is infinite and converges otherwise, though admittedly it's been some time since I had anything to do with this. I'm sure you have a definition in your textbook/lecture notes. Are you sure you're not thinking of the divergence of a series? A series does indeed diverge if the elements don't approach 0.

edit: there is also a possibility that the limit doesn't exit, like with alternating sequences, in which case the sequence diverges also.
 
Last edited:

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