Question about the derivation of Exact Differentials in thermo

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Jacob Nie
Messages
9
Reaction score
4
Homework Statement
There is an equation in Riley's Mathematical Methods that I am confused about:

Applying (4.43) to ##dS##, with variables ##V## and ##T##, we find
$$dU = T \ dS - P \ dV = T\left[ \left(\dfrac{\partial S}{\partial V}\right)_T \ dV + \left(\dfrac{\partial S}{\partial T}\right)_V \ dT\right] - P \ dV.$$
Relevant Equations
Eq 4.43:
$$ dU = \left(\dfrac{\partial U}{\partial X}\right)_Y \ dX + \left(\dfrac{\partial U}{\partial Y}\right)_X \ dY$$
What I don't understand is why ##dS## is expanded in only the two differentials ##dV## and ##dT.## Why doesn't it look more like:
$$dS = \left(\dfrac{\partial S}{\partial V}\right)_{T,P,U} \ dV + \left(\dfrac{\partial S}{\partial T}\right)_{V,P,U} \ dT + \left(\dfrac{\partial S}{\partial P}\right)_{V,T,U} \ dP + \left(\dfrac{\partial S}{\partial U}\right)_{V,T,P} \ dU$$
?
 
  • Like
Likes   Reactions: PhDeezNutz
on Phys.org
In this problem,
the fuller description of the energy is U(S,V) [thinking of the energy as function on the S-V plane]
and
the fuller description of the entropy is S(V,T) [thinking of the entropy as function on the V-T plane].
 
Thank you for the responses - that makes sense.

I forgot to read the sentence of the book that said:
These four quantities are not independent, since only two of them are independently variable.