Question about the derivation of the energy momentum tensor

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SUMMARY

The discussion focuses on deriving the energy-momentum tensor for classical electromagnetism using Noether's theorem, specifically from the Lagrangian density L = -1/4 F^{μν} F_{μν}, where F_{μν} = ∂_μA_ν - ∂_νA_μ. The key equation in question is equation (11), which states that δL/δ(∂_μA_λ) = -F^{μν}. To achieve this result, participants emphasize the importance of applying the product rule correctly while managing the indices involved in the tensor calculus.

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AwesomeTrains
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Hey I'm trying to follow the derivation given here: http://lampx.tugraz.at/~hadley/ss1/studentpresentations/Bloch08.pdf

Homework Statement


As it says in the pdf: "Based on Noether's theorem construct the energy-momentum tensor for classical electromagnetism from the above Lagrangian. L=-1/4 F^{μν} F_{μν} where F_{μν}=∂_μA_ν-∂_νA_μ
I'm stuck at equation (11): \frac{δL}{δ(∂_μA_λ)}=-F^{μν}.
Could someone help me understand how they get this result?

Homework Equations


Some tensor product rule maybe?

The Attempt at a Solution


I would get the result if I use the usual product rule. But how do I treat the indices?
Any tips or redirects to where I can read about it is very appreciated :)

Kind regards
Alex
 
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AwesomeTrains said:
Hey I'm trying to follow the derivation given here: http://lampx.tugraz.at/~hadley/ss1/studentpresentations/Bloch08.pdf

Homework Statement


As it says in the pdf: "Based on Noether's theorem construct the energy-momentum tensor for classical electromagnetism from the above Lagrangian. L=-1/4 F^{μν} F_{μν} where F_{μν}=∂_μA_ν-∂_νA_μ
I'm stuck at equation (11): \frac{δL}{δ(∂_μA_λ)}=-F^{μν}.
Could someone help me understand how they get this result?

Homework Equations


Some tensor product rule maybe?

The Attempt at a Solution


I would get the result if I use the usual product rule. But how do I treat the indices?
Any tips or redirects to where I can read about it is very appreciated :)

Kind regards
Alex

Write the Lagrangian density in terms of the derivatives of the vector potential.
Then use the fact that
## \frac{\partial (\partial_\mu A_\nu)}{\partial (\partial_\sigma A_\tau)} = \delta^\mu_\sigma \delta^\nu_\tau ##
 

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