Understanding Loop Currents: Why is I3 Negative?

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The discussion centers on understanding why I3 is considered negative in the context of loop currents. The confusion arises from the directional flow of currents I2 and I3, which are in opposite directions but both flow from left to right at a specific resistor. The negative sign indicates that I3 flows in the opposite direction compared to I2 at that junction. This does not imply two different reasons for negativity; rather, it reflects the convention of assigning direction in circuit analysis. The conversation emphasizes that the sign merely indicates opposing flow in the cable, which is a fundamental aspect of analyzing loop currents.
Jey
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Hello,
In the following problem, when finding the equation for I2 I don’t understand why I3 is negative. Although I2 and I3 are going in different directions (clockwise and counterclockwise), at that ohm they are both going from left to right. When finding the equation of I1, I1 goes from left to right and I2 right to left, because of that one of the directions is considered negative. Does this mean there are two different reasons for why it is negative? Also, is there a scenario in which it would be positive? I haven’t learned about loop currents before (this is an applications problem), however I tried asking my friends, teacher and searching the internet and I couldn’t find any answers. If you understand how this problem was solved using this method please explain that as well. Thank you!
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At the common cable you get an I2 component and an I3 component, they don't have to go in the same direction once you take the sign into account. The different sign in the solution just means they go in opposite directions in that cable, i.e. the sum is smaller than either I2 or I3's magnitude.
 
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