Question based on laws of motion (inclined motion )

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SUMMARY

The discussion centers on calculating the force (F) required to initiate upward motion of a block on a frictionless inclined plane. The initial attempt yielded the formula F = Mgtan(θ), but the correct formula is F = mg tan(θ/2). Participants emphasized the importance of clearly defining the direction of the applied force and the angle (θ) in the problem. Additionally, the use of a Free Body Diagram (FBD) was recommended to visualize the forces acting on the block.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of inclined plane mechanics
  • Familiarity with Free Body Diagrams (FBD)
  • Basic trigonometry, specifically tangent functions
NEXT STEPS
  • Study the derivation of forces on inclined planes
  • Learn how to construct and interpret Free Body Diagrams
  • Explore the effects of angle changes on force calculations
  • Investigate frictionless motion principles in physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding forces on inclined planes.

Abhishek_R
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Homework Statement


what is the value of F needed so that block begins to move upward on frictionles incline plane .

Homework Equations

The Attempt at a Solution


i made an attemp and got the answer - Mgtan(thetta)
but the real answer is - mgtan(thetta/2)
 
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Hi Abhishek_R, Welcome to Physics Forums.

You'll have to describe your problem more clearly: How (in what direction) is the force F applied? How is the angle ##\theta## defined?

Did you draw a Free Body Diagram? Show us the work you did on your attempt.
 

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