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lavinia said:I think that this thread has lost its seam. The original question that I asked is not being discussed.
On the contrary, I think these are valid responses to your question. The point is that the answers might just no be so simple as you would like.
You ask, with CH being false, what a set of \aleph_1 might look like in \mathbb{R}. The answer is sadly, that we don't know. CH just gives you the answer that such a set exists, without telling you what it looks like or what the properties are.
So if you just accept ZFC+(CH), then your answer is unanswerable.
The closest answer I can give you, is that you can construct a model of ZFC where CH does not hold. You do this through "forcing", this is a very difficult technique. With forcing, you can build an entire universe of sets. In this universe lies a set of real numbers which has cardinality e.g. \aleph_2 and in this universe, you can explicitly find a set of cardinality \aleph_1. But this example of a set will be dependent on the universe you built.
So in general, you cannot construct a set of \aleph_1. However, you can still ask what such a set looks like. In general, there is nothing you can say about such a set. But with additional axioms, there are some things you can say. For example, Martins axiom will tell you that the set has Lebesgue measure 0 (so it will be a Cantor-like set) and is of first category in \mathbb{R}.