Question: electric field within insulator

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SUMMARY

The discussion centers on the creation of a uniform electric field within a glass tube using charged copper tape rings. It is established that electric field lines can pass through insulators, such as glass, but the electric field inside the tube will be zero due to Gauss's law. The simplest method for generating a uniform electric field is through the use of two charged parallel plates, akin to a basic capacitor. The concept of dielectrics is also referenced, indicating that the presence of an insulator alters the electric field characteristics.

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delis16
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I am working on a research project in which i need to create a uniform electric field inside of a tube. I am using a glass tube and wrapping copper tape rings on the outside of the tube. The copper tape is charged to create an electric field. My question is whether or not the field will be present inside of the glass tube. Can electric field lines pass through an insulator and if so is the field any different than if the insulator wasn't there?
 
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delis16 said:
Can electric field lines pass through an insulator and if so is the field any different than if the insulator wasn't there?

The electric field lines would can pass trough an insulator and be somewhat changed(see dielectrics).
http://en.wikipedia.org/wiki/Dielectrics

delis16 said:
I am using a glass tube and wrapping copper tape rings on the outside of the tube. The copper tape is charged to create an electric field. My question is whether or not the field will be present inside of the glass tube

The field will be 0 inside the tube. But not because the field lines are stopped by the insulator but because of Gauss law.
The simplest way to produce a uniform electric field is to use two charged parallel plates. A basic capacitor.

Wait what kind of research are you planing to do if you have so limited knowledge? Take care.
 
First of all the air is insulator and the electric field can pass through it!
I think he is working with discharge system.
If you need the mapping of electric field lines for such system, I will try to look to the equations for that.
 

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