1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Question from higher algebra - hall knight

  1. Apr 4, 2014 #1
    3. The attempt at a solution

    basically i would rewrite the equation as,

    (x/l)/(mb + nc - la) = (y/m)/(nc + la - mb) = (z/n)/(la + mb - nc)

    upon adding,i get
    (x/l + y/m + z/n)/(la+mb+nc)

    but what they provided is,
    (y/m + z/n)/2la = two similar expressions

    ==> (ny + mz)/a = (lz + nx)/b = (mx + ly)/c

    i did not understand how did they get that.

    since this is a proof problem i only used the "3. The attempt at a solution" section.

    Attached Files:

  2. jcsd
  3. Apr 4, 2014 #2
    Image is the question.
  4. Apr 4, 2014 #3


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    As in:

  5. Apr 4, 2014 #4
    ya this is the question sammy.I tried to solve this but couldn't.The explanation they provided couldn't be understood too
  6. Apr 9, 2014 #5


    User Avatar
    Homework Helper

    two facts are being derived and then used
    $$k=\frac{a}{b}=\frac{c}{d}=\frac{e}{f}\rightarrow k=\frac{c+e}{d+f}=\frac{e+a}{f+b}=\frac{a+c}{b+d}$$
    $$k=\frac{c+b}{d}=\frac{a+c}{e}=\frac{b+a}{f}\rightarrow k=\frac{2a}{e+f-d}=\frac{2b}{d+f-e}=\frac{2c}{d+e-f}$$

    So we take the given equation put it in the right form and transform it the first way then we put it in the form needed and transform again. finally we put it in the form of the answer.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted