How is Kinetic Energy of an Alpha Particle in Nuclear Decay Determined?

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SUMMARY

The kinetic energy of an alpha particle emitted during the decay of Uranium-238 (U-238) is calculated to be 4.8 x 10-13 joules. The initial velocities of the alpha particle and the resulting thorium nucleus are determined to be 1.20 x 107 m/s and 2.05 x 105 m/s, respectively. Additionally, the difference between the rest mass of the original uranium nucleus and the sum of the rest masses of the decay products is calculated to be 5.42 x 10-30 kg. These calculations are essential for understanding the energy dynamics in nuclear decay processes.

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a U(a=238,z=92) originally at rest decays spontaneously to form thorium and an alpha particle.no gamma rays is emitted
(a):the alpha particle emitted during decay travels a distance of 25mm in a cloud chamber.given that on average alpha particle creates 4 *raise to power 3 ions per mm of track in cloud chamberand energy required to poduce one ion pair is 4.8*raise to power -18 j.find kinetic energy with which alpha particle was emitted.
(b):hence deduce the initial velocities of alpha particle and thorium nucleus
c:calculate the difference between the rest masses of original uranium nucleus and sum of product of rest masses of products of decay
please solve them for me
answers:
a:4.8*raise to power -13j
b:velocity of alpha:1.20*raise to power 7 m/s
velocity of thorium :2.05*raise to power 5 m/s
c:mass:5.42* raise to power -30 kg
please post the complete process h did u solve this question
 
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