Question on 2nd Order Circuit Assignment: Capacitor Voltage Divider Calculation

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The discussion focuses on a question regarding the calculation of capacitor voltage in a 2nd order circuit assignment, specifically addressing the voltage divider rule. The user assumes an inductor is a capacitor with a capacitance of 0.2F and presents the formula Vc = V1*(5+5p)/(10+5+5p) for calculating the voltage across the capacitor. Another participant suggests clarifying with the professor due to potential errors in the assignment figures, which may affect the circuit topology and subsequent calculations.

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http://www.ece.ubc.ca/~shahriar/eece251_notes/eece251_assignment7.pdf

Hey guys, I have a question about my 2nd order circuit assignment. I posted the link to my assignment, and the question I have is question 2. I know that the question saids its a capactior and the circuit diagram itself has an inductor, but here we assume that the inductor is a capacitor with 0.2F.

On with my question

So Basically I was wondering if the voltage across the capactior would be a voltage divider of the node 1 ( top node) when the switch is operated, so i would have

Vc = V1*(5+5p)/ (10+5+5p)
 
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Larrytsai said:
http://www.ece.ubc.ca/~shahriar/eece251_notes/eece251_assignment7.pdf

Hey guys, I have a question about my 2nd order circuit assignment. I posted the link to my assignment, and the question I have is question 2. I know that the question saids its a capactior and the circuit diagram itself has an inductor, but here we assume that the inductor is a capacitor with 0.2F.

On with my question

So Basically I was wondering if the voltage across the capactior would be a voltage divider of the node 1 ( top node) when the switch is operated, so i would have

Vc = V1*(5+5p)/ (10+5+5p)

I think I'd clarify with the professor first -- it looks like they got Figures 1 & 2 swapped, and they are slightly different topologies. I think the figures probably should be swapped back before solving either question...
 
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