Larrytsai said:http://www.ece.ubc.ca/~shahriar/eece251_notes/eece251_assignment6.pdf
Question 4 on the link.
I understand why the top inductor to the left has i = 0A but I don't understand why it has a voltage of 3.816V, can anyone care to explain?
The formula for calculating the voltage and current in a second order circuit is V(t) = V(0)e^(-t/RC)cos(ωt - φ) for a capacitor and I(t) = I(0)e^(-t/RC)cos(ωt + φ) for an inductor, where V(t) and I(t) are the voltage and current at a given time t, V(0) and I(0) are the initial voltage and current, RC is the time constant of the circuit, ω is the frequency of the AC source, and φ is the phase angle.
In a second order circuit with inductors and capacitors, the voltage and current oscillate sinusoidally with a decaying amplitude over time. This is due to the energy stored in the inductor and capacitor being constantly transferred back and forth between them.
The value of the inductor or capacitor affects the time constant of the circuit, which in turn affects the rate at which the voltage and current oscillate. A larger value for the inductor or capacitor will result in a longer time constant and slower oscillations, while a smaller value will result in a shorter time constant and faster oscillations.
If the AC frequency is changed, the voltage and current will change accordingly. The time constant of the circuit will also change, which will affect the rate of oscillation.
The phase angle in a second order circuit represents the phase difference between the voltage and current. It is an important factor in determining the behavior of the circuit and can be used to calculate the power factor, which is a measure of how efficiently the circuit is using the energy from the AC source.