Question on corner and resonant frequencies

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SUMMARY

The discussion centers on calculating corner and resonant frequencies for an RC filter and an RLC circuit. The corner frequency for the RC filter, using a resistor R1 of 3 kOhms and a capacitor C of 8 nFarads, is determined to be 6.631 kHz. For the RLC circuit with a resistance R of 12.4 kOhms, an inductance L of 9 µHenries, and a capacitance C of 3.1 µFarads, the resonant frequency is calculated to be approximately 952.836 Hz. The equations used are fc = 1/(2*pi*R*C) for the RC filter and fr = 1/(2pi*sqrt(L*C)) for the RLC circuit.

PREREQUISITES
  • Understanding of RC and RLC circuit configurations
  • Familiarity with frequency calculations in electrical engineering
  • Knowledge of the units of resistance (Ohms), capacitance (Farads), and inductance (Henries)
  • Proficiency in using mathematical constants such as pi
NEXT STEPS
  • Study the effects of varying resistance and capacitance on corner frequency in RC filters
  • Learn about the implications of resonant frequency in RLC circuits
  • Explore advanced filter design techniques using operational amplifiers
  • Investigate the role of damping in RLC circuits and its effect on performance
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in filter design and analysis will benefit from this discussion.

Mohamed Abdul

Homework Statement


1. An RC filter is constructed by modifying a voltage divider. The top resistor R1 = 3kOhms remains the same but the bottom resistor R2 is replaced by a capacitor C = 8nFarads. Determine the corner frequency fc for this filter in kHertz.

2. For an RLC circuit R = 12.4 kOhms, L = 9 uHenries, and C = 3.1 uFarads.Here u stands for micro ... there are no Greek letters in Blackboard., find the resonant frequency fc in kHz.

Homework Equations


fc = 1/(2*pi*R*C) fr = 1/(2pi*sqrt(L*C))

The Attempt at a Solution


For number 1, I plugged in R and C, and got 1/(2*pi*3000*8*10^-9) and got 6.631 kHz. For the second one, I got 1/(2pi*sqrt(9*10^-9*.0000031)) and got 952.836 Hz

I'm not to sure about my solutions, especially number 2, where I'm not sure if the equation I used was the correct one.
 
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Gonna bump this thread as I'm still not sure if my method was correct here.
 

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