- #1
pillow47
- 8
- 0
Dear PF,
I'm reading a book on DFT, and it says that only ground-state wave function is a unique functional of the ground-state density, n(r). However, if in DFT the potential, v(r), is a unique functional of n(r), then shouldn't all wave functions be functionals of n(r), because you can just solve for the excited-state wave functions from the v(r) determined from n(r)?
Thanks
I'm reading a book on DFT, and it says that only ground-state wave function is a unique functional of the ground-state density, n(r). However, if in DFT the potential, v(r), is a unique functional of n(r), then shouldn't all wave functions be functionals of n(r), because you can just solve for the excited-state wave functions from the v(r) determined from n(r)?
Thanks