I Question on derivation of a property of Poisson brackets

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The discussion centers on the canonical transformation defined by Alexei Deriglazov in his book "Classical Mechanics," specifically regarding the preservation of Hamiltonian equations of motion. Deriglazov asserts that the partial derivatives of the Poisson bracket with respect to the new coordinates must be zero, leading to the conclusion that the Poisson brackets can be expressed as a function of time. An explicit calculation in a subsequent chapter supports this for a two-dimensional phase space, showing that the derivatives of the Poisson bracket are zero under time-independent transformations. However, the challenge arises when extending this reasoning to higher dimensions, where the relationship between the arbitrary derivatives of the Hamiltonian and the multiple Poisson bracket derivatives complicates the conclusion. The discussion raises questions about how to generalize the findings for dimensions greater than two, given the complexity of the equations involved.
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The textbook Classical Mechanics by Deriglazov presents a proof of the fact that Poisson brackets are at most function of time in a canonical transformation. While the proof seems convincing for a 2D phase space, it appears to the OP at least incomplete for greater dimensions
The book Classical Mechanics by Alexei Deriglazov defines as canonical a transformation Z=Z(z,t) that preserves the Hamiltonian form of the equation of motion for any H. After taking the divergence of the vector equation relating the components of the time derivative of Z in the two coordinate systems, he writes (p. 116, I modify slightly the notation) the following equation (it is intended that repeated indices sum):

$$
\frac{\partial{}}{\partial{Z_k}}\left(\left\{Z_k,Z_l\right\}_z|_{z(Z,t)}\right)\frac{\partial{H(z(Z,t))}}{\partial{Z_l}}+\frac{\partial{}}{\partial{Z_k}}\left(\frac{\partial{Z(z,t)}}{\partial{t}}\Big{|}_{z(Z,t)}\right)=0.
$$

He asserts that, since H is arbitrary, the partial derivatives of each Poisson bracket

$$
\left\{Z_k,Z_l\right\}_z\Big{|}_{z(Z,t)}

$$

with respect to the Z coordinates must be 0 and so we can at most write (the substitution z=z(Z,t) can be omitted):

$$
\left\{Z_k,Z_l\right\}_z=c_{kl}\left(t\right)
$$

The derivation seems confirmed by an explicit calculation that the author does in the following chapter (p. 138 and 142), where he considers the phase space of dimension 2d=2. For the case e.g. of a time-independent transformation, he takes the derivatives of the two equations for the time derivatives of Q and P and adds them, according to the discussion above, obtaining (without explicitly showing the variable dependency):

$$
\frac{\partial{}}{\partial{Q}}\left(\left\{Q,P\right\}\right)\frac{\partial{H}}{\partial{P}}-\frac{\partial{}}{\partial{P}}\left(\left\{Q,P\right\}\right)\frac{\partial{H}}{\partial{Q}}=0
$$

In this case, the arbitrariness of H forces us to conclude that both partial derivatives of {Q,P} with respect to Q and P are 0, thus verifying the assertion for this case (there's no time dependence here so we can conclude {Q,P}=c=constant).

Turning back to the general assertion for 2d>2, how can such an approach lead to the desired conclusion (i.e. that all partial derivatives of the {Z
i,Zj} with respect to Zk are 0)
if we have only one equation in the 2d arbitrary partial derivatives of H which potentially multiply 2d
2(d-1)/2 partial derivatives of the Poisson brackets ? The d terms would collect many different partial Poisson bracket derivatives, leaving us with no possibility to conclude that each of the four partial derivative, for every Poisson bracket, is zero.
 
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