Question on gravitational field

Click For Summary
SUMMARY

The discussion centers on calculating the distance from Earth at which a space capsule experiences zero gravitational force due to the Earth and the Moon. The masses of the Earth (5.98 x 1024 kg) and the Moon (7.35 x 1022 kg) are provided, along with their respective orbital radius (3.84 x 108 m) and radius (6.38 x 106 m). The initial calculation yielded a distance of 3.79 x 108 m, but the correct answer is 3.46 x 108 m, indicating an error in the numerical computation rather than the symbolic result.

PREREQUISITES
  • Understanding of gravitational fields and forces
  • Familiarity with Newton's law of universal gravitation
  • Ability to manipulate algebraic equations
  • Basic knowledge of physics concepts related to celestial bodies
NEXT STEPS
  • Review calculations involving gravitational forces between two bodies
  • Study the concept of gravitational equilibrium points
  • Explore the application of Newton's law of gravitation in multi-body systems
  • Learn about the mathematical derivation of gravitational field equations
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces and celestial mechanics, as well as educators seeking to clarify concepts related to gravitational fields.

gaobo9109
Messages
68
Reaction score
0

Homework Statement


Considering only the gravitational fields of the Earth and the Moon, find the distance from the Earth at which a space capsule traveling between the Earth and the Moon is subject to zero gravitational force.

Mass of the Earth = 5.98 x 1024kg
Mass of the Moon = 7.35 x 1022kg
Radius of Moon's orbit = 3.84 x 108m
Radius of the Earth = 6.38 x 106m
Radius of the Moon = 1.74 x 106m


Homework Equations





The Attempt at a Solution



Let x be the distance between the centre of Earth and the point of zero gravitational field

Gravitational field due to Earth = Gravational field due to Moon
GME/x2 = GMM/(R - x)2
(ME/MM)1/2=x/(R-x)
x = (ME/MM)1/2R/((ME/MM)1/2 +1)
= 3.79 x 108

But the answer provided is 3.46 x 108

Can anyone tell me where I went wrong?
 
Physics news on Phys.org
Since the symbolic result is correct you must have made an error during the actual calculation of the number.
 

Similar threads

Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K