Question on Hydrates and Reactions

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SUMMARY

The discussion centers on the proper representation of copper (II) chloride dihydrate (CuCl2·2H2O) in chemical equations when dissolved in water for reactions involving aluminum. Participants emphasize that while the dihydrate form contributes to the mass of the compound, it can be represented differently depending on the context of the reaction. The consensus is that including the dihydrate in the formula is essential for accurate stoichiometric calculations, especially when determining the concentration of the original solution. The discussion highlights the importance of context in chemical notation.

PREREQUISITES
  • Understanding of chemical equations and stoichiometry
  • Knowledge of hydration and its effects on molecular mass
  • Familiarity with ionic compounds and their states (solid, aqueous)
  • Basic principles of chemical reactions involving metals and salts
NEXT STEPS
  • Research the properties and reactions of copper (II) chloride dihydrate (CuCl2·2H2O)
  • Learn about stoichiometric calculations in aqueous solutions
  • Explore the significance of hydration in chemical reactions
  • Study the representation of ionic equations in various contexts
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Chemistry students, educators, and professionals involved in chemical reactions, particularly those focusing on stoichiometry and the behavior of hydrated compounds in solution.

rosyposy
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Hey! I am currently working on a project where I have to react copper (II) chloride dihydrate (dissolved in water) and aluminum. When writing the equation and the ionic equation for this, would you include the dihydrate in the formula since it’s dissolved in water and no longer in its crystalline form or would you still write it as CuCl2.2H2O, can you also provide an explanation for the correct way to write since I am really confused as some sites write it with the H2O and some don’t. Thank you!
 
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The water of hydration - .2H20 - adds mass to the molecule. So, if are going to get a dry weight to assay some reaction in a solution you have to include it. Is that what you are asking? You can write the reaction ignoring the extra mass but I do not see any immediate benefit other than teaching an introduction.
Practical aspect is what you have dictates what you do:
Copper chloride appears as a yellowish-brown powder (the anhydrous form) or a green crystalline solid (the dihydrate). The green stuff is usually what you have. If have the brown stuff you would measure the mass of copper chloride with no water to worry about.
 
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Hey, so I am only weighing the copper retrieved from the reaction to find the concentration of the original solution using stoichiometry, but I also need to write the formula for the whole reaction with states so I was just asking if I would write the copper (II) chloride dihydrate as a dihydrate since it is dissolved in water and I’m not sure if you are supposed to write dihydrates as aqueous since they exist in crystalline form.
 
There is no simple yes/no answer to your question.

A lot depends and what you want to show. Every way of writing the reaction has its own applications and makes sense in different contexts.
 

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