Question on Optics, finding images of a pin using a concave mirror

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Homework Help Overview

The discussion revolves around a problem in optics involving a concave mirror and the image formation of a pin placed at an angle to the principal axis. The original poster seeks assistance in determining the positions of the image points A' and B', as well as the nature and magnification of the image.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of magnification and its calculation based on the size of the image and object. There are inquiries about the object distance for the pin and the specific positions of the image points A' and B'. Some participants question the assumptions made regarding the nature of the image.

Discussion Status

There is an ongoing exchange of ideas, with some participants providing guidance on how to approach the problem. The original poster expresses uncertainty and seeks clarification, while others encourage sharing visual aids and previous work to facilitate understanding. Multiple interpretations of the problem are being explored.

Contextual Notes

The original poster mentions feeling unsure about their previous attempts and expresses a desire for assistance without providing a complete solution. There is a focus on understanding the image formation process and the calculations involved.

Krishna0703
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A pin AB, 1cm long, is placed at an angle to the principal axis in front of a concave mirror, of focal length 5cm. Point B lies on the principal axis at a distance of 4 cm. Point A is such that the angle ABP is 60°, where P, the pole, is the point where the principal axis intersects the mirror.



a.) Find the positions of A' and B' of the needle's image.
b.) Determine the image's nature and magnification.


I have attempted to the solution but still i feel am in a sort of foolish mistakes...would be grateful if anyone can help me please. after going through the physics, i am sure and convinced that the image is an erected, magnified and virtual now...and obtained magnification as 3. part a.) of the question is unsure...can u help with an answer please...
 
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Hi, Krishna,

Can you show a picture, and your work, please? You must be on the right track, as the image is virtual. ehild
 
Last edited:
sure...i will take a snap of it and share it here..can u download the files please..then u zoom on it for better view...sorry for the scrap i written...but am a poor student...that already embarrasses me
 

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Is the magnification not defined as the seize of the image divided by the seize of the object ?

I do not see if you did anything to find the image of A. See my drawing.
What is the object distance for the red object? Note, that the length of the pinl=1 cm. Find the position of A' and determine the length A1B' to get the magnification.

ehild
 

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can u help me with a work solution for this time please?
 
I do not understand what is a work solution you expect from me. I am just trying to help. The point A is at the peak of the red arrow in my previous picture. Determine the position and size of the image of the red arrow: Its peak is the image of A.
For that, you need the object distance, do, it is shorter than it was for B. Therefore, the magnification will be different for A and B.

ehild
 
okki, i got it, am off to my desk to work it out ehild..thanks.
 

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