1. The problem statement, all variables and given/known data http://www.xtremepapers.com/CIE/International A And AS Level/9709 - Mathematics/9709_w03_qp_6.pdf question 6 b ii 2. Relevant equations 3. The attempt at a solution The concept is bothering me. the answer is 5! × 3! × 4C1. Why is it a permutation problem? Plus why do we use 5! × 3! in a permutation problem, isn't it used in combinations? as 5!X 3! shows the nos of ways it can be arranged 'in any order' So how can we use that in a permu where order DOES matter! The reason I think its a permutation problem is because of http://answers.yahoo.com/question/index?qid=20110530100750AAXrtRp other than that I dont relly know why it is a permutation problem even.