A bowler throws a bowling ball of radius R = 11 cm along a lane. The ball (the figure) slides on the lane with initial speed vcom,0 = 7.8 m/s and initial angular speed ω0 = 0. The coefficient of kinetic friction between the ball and the lane is 0.13. The kinetic frictional force http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c11/low_fvec.gifkacting on the ball causes a linear acceleration of the ball while producing a torque that causes an angular acceleration of the ball. When speed vcom has decreased enough and angular speed φ has increased enough, the ball stops sliding and then rolls smoothly. During the sliding, what are the ball's (a) linear acceleration and (b) angular acceleration? (c) How long does the ball slide? (d) How far does the ball slide? (e) What is the linear speed of the ball when smooth rolling begins? Note that the clockwise direction is taken as negative.
Second Laws: F=m*a and. Torque=I*angular acceleration
I=(2/5)mR^2 ------ this I am not sure. This is probs where i went wrong.
The Attempt at a Solution
For part a, I used newtons second law
thus a=-frictionconstant * 9.8=-1.274
I had this expression, Iα=R*μ*m*g
where i too I to be I=(2/5)mR^2
and i got α=28.9545
But this is WRONG
Part C i got 1.74927... which is correct
Part D is wrong followed by the wrong answer from part B
Part e i got the right answer
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