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An electron beam is send perpendicular onto an electric field between two capacitor plates. The electrons got their kinetic engergi by being accelerated through a potential difference

The distance between the plates is d, and the length of the plates is a in the direction the electrons move. The electric field is uniform between the plates and 0 outside the plates.The electrons do not hit the plates.

Calculate the angle that the electron beam is deflected by the passage through the space between the plates. How does the angle depend on the potential difference?

This may sound stupid, but i have spend an hour just searching for a formula i could use to solve this problem. I have no idea how to get the angle into a formula.

First i would try to fin the electric field.

So first (Q/V)=e

and the use F=q(E+VxB)

But im not really sure if this even makes any sense, can anyone help me get started?

F=q(E+VxB)

*V*. The potential difference between the capacitor plates are also*V*.The distance between the plates is d, and the length of the plates is a in the direction the electrons move. The electric field is uniform between the plates and 0 outside the plates.The electrons do not hit the plates.

Calculate the angle that the electron beam is deflected by the passage through the space between the plates. How does the angle depend on the potential difference?

This may sound stupid, but i have spend an hour just searching for a formula i could use to solve this problem. I have no idea how to get the angle into a formula.

First i would try to fin the electric field.

So first (Q/V)=e

_{0}(A/d) isolate to find Qand the use F=q(E+VxB)

But im not really sure if this even makes any sense, can anyone help me get started?

F=q(E+VxB)