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Anti-Crackpot

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Deuterium Spectrum (nm) 410.07, 433.93, 486.01, 656.11

I came upon these figures on a commercial product site for Deuterium lamps. So, question: Are they correct? If so, then...

364.5068222*(3^2/(3^2 - 4)) = 656.11

364.5068222*(4^2/(4^2 - 4)) = 486.01

364.5068222*(5^2/(5^2 - 4)) = 433.93

364.5068222*(6^2/(6^2 - 4)) = 410.07

364.5068222... = 4 / .010973731568539 where 1.0973731568539*10^7 m^-1 is the Rydberg Constant (R). Yes, I know 4/R is supposed to equal B, the Balmer constant, but I also know there is a Balmer_H, for Hydrogen, which is different from 4/R exactly, so it seems to me this is a bit of an odd coincidence and I'm not quite sure what to make of it.

Compounding my confusion is that, empirically, here is how you achieve a match with light hydrogen Fraunhofer lines in the visible spectrum:

364.6006*(3^2/(3^2 - 4)) = 656.281 = H_alpha

364.6006*(4^2/(4^2 - 4)) = 486.134 = H_beta

364.6006*(5^2/(5^2 - 4)) = 434.048 ~ H_gamma (vs. 434.047)

364.6006*(6^2/(6^2 - 4)) = 410.176 ~ H_delta (vs. 410.175)

4 / 364.6006 = 0.010970909, but I can't seem to find 1.097090 * 10^7 m^-1 anywhere in the literature. The figure I have seen for R_H is ~ 1.09678 * 10^7 m^-1.

In trying to sort this out I'm thinking the first step is simply to know if I am actually dealing with the right figures for the deuterium emission spectrum as per the question in the first paragraph and/or how they are mathematically derived. So any help there would be greatly appreciated.

TIA,

AC

I came upon these figures on a commercial product site for Deuterium lamps. So, question: Are they correct? If so, then...

364.5068222*(3^2/(3^2 - 4)) = 656.11

364.5068222*(4^2/(4^2 - 4)) = 486.01

364.5068222*(5^2/(5^2 - 4)) = 433.93

364.5068222*(6^2/(6^2 - 4)) = 410.07

364.5068222... = 4 / .010973731568539 where 1.0973731568539*10^7 m^-1 is the Rydberg Constant (R). Yes, I know 4/R is supposed to equal B, the Balmer constant, but I also know there is a Balmer_H, for Hydrogen, which is different from 4/R exactly, so it seems to me this is a bit of an odd coincidence and I'm not quite sure what to make of it.

Compounding my confusion is that, empirically, here is how you achieve a match with light hydrogen Fraunhofer lines in the visible spectrum:

364.6006*(3^2/(3^2 - 4)) = 656.281 = H_alpha

364.6006*(4^2/(4^2 - 4)) = 486.134 = H_beta

364.6006*(5^2/(5^2 - 4)) = 434.048 ~ H_gamma (vs. 434.047)

364.6006*(6^2/(6^2 - 4)) = 410.176 ~ H_delta (vs. 410.175)

4 / 364.6006 = 0.010970909, but I can't seem to find 1.097090 * 10^7 m^-1 anywhere in the literature. The figure I have seen for R_H is ~ 1.09678 * 10^7 m^-1.

In trying to sort this out I'm thinking the first step is simply to know if I am actually dealing with the right figures for the deuterium emission spectrum as per the question in the first paragraph and/or how they are mathematically derived. So any help there would be greatly appreciated.

TIA,

AC

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