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Here's an example that helps illustrate my question:
Prove: A sequence in R can have at most one limit.
Proof:
Assume a sequence {xn}n[tex]\in[/tex]N has two limits a and b.
By definition:
-For any [tex]\epsilon[/tex]>0, there exists an N[tex]\in[/tex]N such that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex]/2.
-A similar argument can be made for the limit b.
Thus:
|a-b| [tex]\leq[/tex] |xn-a| - |xn-b| < [tex]\epsilon[/tex]/2 + [tex]\epsilon[/tex]/2 = [tex]\epsilon[/tex]
Thus a=b.
Now here's my question...in the step immediately following "By definition," the actual definition of a limit of a sequence shows that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex], not that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex]/2. So is it acceptable to put [tex]\epsilon[/tex] over any number when convenient in a proof? As in the above proof, it is convenient to put [tex]\epsilon[/tex]/2 instead of just [tex]\epsilon[/tex] so that in the final step the two add up to [tex]\epsilon[/tex] and show that a=b.
Thanks.
edit: sorry for the awkward formatting, if anything is unclear, let me know I'll explain it in words.
Prove: A sequence in R can have at most one limit.
Proof:
Assume a sequence {xn}n[tex]\in[/tex]N has two limits a and b.
By definition:
-For any [tex]\epsilon[/tex]>0, there exists an N[tex]\in[/tex]N such that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex]/2.
-A similar argument can be made for the limit b.
Thus:
|a-b| [tex]\leq[/tex] |xn-a| - |xn-b| < [tex]\epsilon[/tex]/2 + [tex]\epsilon[/tex]/2 = [tex]\epsilon[/tex]
Thus a=b.
Now here's my question...in the step immediately following "By definition," the actual definition of a limit of a sequence shows that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex], not that n[tex]\geq[/tex]N implies that |xn-a| < [tex]\epsilon[/tex]/2. So is it acceptable to put [tex]\epsilon[/tex] over any number when convenient in a proof? As in the above proof, it is convenient to put [tex]\epsilon[/tex]/2 instead of just [tex]\epsilon[/tex] so that in the final step the two add up to [tex]\epsilon[/tex] and show that a=b.
Thanks.
edit: sorry for the awkward formatting, if anything is unclear, let me know I'll explain it in words.
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