Question Regarding Impulse and momentum

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    Impulse Momentum
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Homework Help Overview

The discussion revolves around the effectiveness of rubber versus lead bullets in knocking down a bear, focusing on the concepts of impulse and momentum. Participants explore the implications of using bullets with the same momentum but different material properties.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the differences in behavior between rubber and lead upon impact, particularly regarding momentum and energy transfer. There are discussions about the implications of collision time and the resulting forces involved.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants have offered insights into the nature of momentum and its vector properties, while others are seeking clarification on specific concepts like change in momentum (Δp) and the effects of bouncing.

Contextual Notes

There is a noted confusion regarding the definitions and implications of momentum and impulse, as well as the assumptions about the mass of the bullets. Participants are also navigating language barriers, which may affect their understanding of the physics concepts discussed.

  • #31
hmm :redface:

have you done conservation of momentum? :smile:

if so, what is the equation for conservation of momentum for rubber bouncing off a wall on ice (ie, no foundations, so the wall can slide along the ice, but the wall is initially stationary)?
 
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  • #32
kashan123999 said:
Lead... Change in momentum= final - intial = 0-mv=-mv i guess? opposite to the direction of original propagation...

Rubber bullet... mu-mv = m(u-v) ??
I was trying hard not to confuse you on this. You can think in terms of speeds or in terms of velocities. Because all the movement is in the same straight line, but in opposite directions, the difference is how the sign is handled. In my previous post I defined u as a speed, but you seem to be using velocities, so I'll stick with that.
If u and v are velocities measured in the same direction then the momenta are mu and mv, and the change in momentum is mu-mv, as you wrote. But note that u will be negative. So if you compare the magnitude of -mv (change in momentum for the lead) with that of m(u-v) (change in momentum for the rubber), which is larger?
 
  • #33
I don't know :( i am confused as hell,Tommorow is my physics exam,please tell me the answer,i can develop critical skills later on :D I am a pakistani so that really makes me a rote learner and far far behind the world sorry :D so,what is the detailed answer?
 
  • #34
have you done conservation of momentum?
 
  • #35
tiny-tim said:
have you done conservation of momentum?

yep,initial momentum = final :@ change in momentum = 0
 
  • #36
kashan123999 said:
yep,initial momentum = final

ok, so try applying total initial momentum = total final momentum to rubber bouncing off a wall on ice (ie, no foundations, so the wall can slide along the ice, but the wall is initially stationary)
 

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