1. The problem statement, all variables and given/known data The position of an object at three different times is given At t= 4.9s position= (4.0,3.1,0) m At t= 5.4s position = (1.3, 7.1, 0) m At t= 5.9s position = (-0.8,12.7,0) m Using the best information available, what was the displacement of the bee during the time interval from 4.9 s to 4.93 s? The earlier parts of this question asked for the average velocity of the object between 4.9s and 5.4 s (-5.4,8,0) m/s And the average velocity between 4.9s and 5.9 s which is (-4.8, 9.6, 0) m/s. 2. Relevant equations Displacement formula = r2 - r1 where r2 is the final position of the object and r1 is the initial position and also, r2 = r1 + (Average Velocity)(change in time) 3. The attempt at a solution The way I attemped this solution is to use the average velocity between 4.9 s and 5.4 s (which was found earlier) and plug all the given values into the formula: r2= r1 + (Average Velocity)(Change in time) Which would be, (4.0,3.1,0) + ((-5.4,8,0)(0.93)) = (-1.022, 11.1, 0) = r2 I would then use this value for r2 into the formula for finding the displacement (r2 - r1) (-1.022,11.1,0) - (4.0,3.1,0) = (-5.022, 8, 0) m So the final answer would be (-5.022, 8, 0) m However, I'm still kind of sketchy on this solution and would just like some confirmation whether this is the right way of doing a question like this.