...This isn't a homework problem or anything, I'm just a bit confused about this and have a test coming up. So any clarification would be greatly appreciated...(adsbygoogle = window.adsbygoogle || []).push({});

http://www.synthdriven.com/images/deletable/24-4.jpg [Broken]

We were just recently introduced to the concept of electrostatic potential, and it was defined as U. However, when it comes to a capacitor, this quantity U pops up once again in the following equation:

[tex]U=\frac{1}{2}CV^2[/tex]

Where U is explained as the total energy stored by the given capacitor...

Now, I know that U=-W. However, this phrasing has me confused. I know that the work is equivalent to the energy stored within a capacitor because the energy stored within the capacitor is the same as the amount of work done on the capacitor, right??

However, that formula doesn't seem to work in this situation because we're talking about a single test charge within the electric field of the capacitor... It's much more microscopic... So would I then use something like W=qV??

But even then, I need V, and in order to find V I'd need C...

I'm just a bit confused on how to go about this, I believe I'm confusing concepts, and any sort of explaination to sort this out would be greatly appreciated.

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Question Regarding Work Done By Capacitor

**Physics Forums | Science Articles, Homework Help, Discussion**