Question related two different ways to do solution

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AI Thread Summary
The discussion revolves around the different methods used to solve a problem involving cross-section sidelengths. One method expresses the sidelength as 8-8x/3, while the other relies on similar triangle relationships. The user questions the correctness of both approaches and seeks clarification on which answer is accurate, either 470 kJ or 117 kJ. There is also a suggestion to try the integral method indicated in red. The conversation highlights the complexities of solving the problem and the potential for multiple valid approaches.
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Homework Statement
An upside-down square pyramid with a height of 3 m and side lengths of 8m is filled to the brim with water. How much work is needed to lift all the water out of the container through the top. (ρ = 1000 kg/m3, g = 9.8 m/s2)
Relevant Equations
Work = Force * displacement
My work:
Screenshot 2025-04-12 203210.png


Answer Key (red font one) *may not be right.

My question is why is sidelength of cross section written as 8-8x/3, while my way of doing it doesn't involve that (involves suspicious similar triangle relationships)? Which answer (if any) is right here? 470 kj or 117 kj? Thank you!

Screenshot 2025-04-12 203210.png


Screenshot 2025-04-12 203309.png
 
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Did you try doing the integral in red?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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