Question relates to Degree and some other simple question.

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SUMMARY

This discussion focuses on solving physics problems involving motion, specifically using kinematic equations. Marcia's car decelerates from 19.2 m/s at a rate of 6.2 m/s², taking 3.1 seconds to stop after a 0.13-second delay. The distance traveled during this deceleration is calculated using the equation Δx = V0Δt + 0.5a(Δt)². Additionally, Ali's projectile motion problem involves a ball thrown at a 60-degree angle with an initial speed of 25 m/s, while Maxim's acceleration problem calculates the distance traveled by a car accelerating at 5.2 m/s².

PREREQUISITES
  • Understanding of kinematic equations for linear motion
  • Knowledge of projectile motion principles
  • Familiarity with acceleration and deceleration concepts
  • Ability to interpret and create velocity-time graphs
NEXT STEPS
  • Study the kinematic equations in detail, particularly Δx = V0Δt + 0.5a(Δt)²
  • Learn about projectile motion calculations, including angle and initial velocity effects
  • Explore the concept of negative acceleration and its implications in motion
  • Practice drawing and interpreting velocity-time graphs for various motion scenarios
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Students studying physics, educators teaching motion concepts, and anyone interested in applying kinematic equations to real-world scenarios.

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1. Marcia was driving her car at the constant speed of 19.2 m/s when she saw the light turn red. It took her .13 sec to hit the brakes, but then the car slowed at the constant rate of 6.2 m/s2 until it stopped. How much time did it take for the car to stop moving after the light turned red.? How far did the car travel until it stopped?
Did I plug in the right number for each symbol?


I am confuse of which equation to use and which question should I put .13s to.

First question:

V0 = 19.2 m/s
A = -6.2 m/s 2
Δt = ?

Δx=?

Δx = V0Δt + .5a(Δt)2

Second question:
V0 = 19.2 m/s
A = -6.2 m/s 2
Δt = .13 s

Δx=?

Δx = V0Δt + .5a(Δt)2

2. Standing on a flat roof of a 21 m high building, Ali threw a ball up at a 60 degree angle to the roof top. The speed of the ball was 25 m/s. When the ball left Ali’s outstretched hand the ball was 3.1 meters from the roof top. The ball eventually landed on the roof. High far was the ball from Ali?

I never work on question related to degree, so I am pretty lost on this one.
Vo = 25m/s
A = -9.8 m/s 2
Vf = 0 m/s
Δx = ?







3. Maxim was driving his car at 15 m/s when he pressed the gas pedal down to accelerate at 5.2 m/s2. How far did he travel in the next 2.5 seconds?

I think this is correct.
Δx = ?
V0 = 15 m/s
Δt = 2.5 s
A = -5.2 m/s 2

Δx = V0Δt + .5a(Δt)2

Δx = 15 m/s (2.5 s) – 5.2 m/s 2 (2.5 s 2)

Δx = 37.5 m – 32.5 m

Δx = 5m
 
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1. Draw a velocity - time graph.
2. Not sure how the rooftop and roof configuration.
3. Why the acceleration is negative? Draw a velocity- time graph here too.
 
Last edited:

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