Need a little push. [Simple Physics Problems]

[Emilyneedshelp]

Homework Statement

Question
A car starts from rest and uniformly increases its speed at a rate of 0.7 m/s2 on a circular track of radius R = 253 m. What is the magnitude of the car’s net acceleration after 50 s?

a_cen=.7m/s^2
t=50s
R=253m

Homework Equations

Equations
a_cen=(v^2)/r
Maybe?
ω=Δθ/Δt
a=r(Δω/Δt)

The Attempt at a Solution

√[a_T^2 + a_C^2]

a_C=.7m/s^2
a_T= r(dω/dt)√[.7(253)]=v
v=13.308m/s

v(50s)=S
S=665.4

S/r=θ
θ=2.63rad

ω=(2.63rad/50s)
ω/50=α

α=.001052rad/s^2
α(253)=a_T

a_T=.26616
a=√[a_T^2 + a_C^2]
a=.74489m/s^2

Answer is not correct, is there something wrong with my logic?

 

[billy_joule]

The given acceleration is how fast the cars speedometer is changing. (I.e.the change in the magnitude of the tangential velocity with time).
Not a_cen as you've used it.

 

[Emilyneedshelp]

Thank you, I solved it. How silly of me not to realize that.