Question with solution, confused on how time was found.

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SUMMARY

The discussion centers on a physics problem involving a skier with a mass of 59.0 kg sliding down a ski jump from a height of 6.60 m and taking off horizontally. The key equation used to determine the time of fall, t, is derived from the one-dimensional motion equation, resulting in t = sqrt(2h/g), where g represents gravitational acceleration. The forum participants clarify the definitions of D, h, and H, emphasizing the importance of understanding the relationship between vertical distance and time in projectile motion.

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Homework Statement


A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 6.60 m and D = 10.6 m, find H.

Homework Equations

The Attempt at a Solution



The solution was provided, this is a sample problem. I'm just very confused in how t was found to be sqrt(2h/g)

http://imgur.com/a/UuRNp

UuRNp
 
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I assume you are referring to the fourth line where time was substituted out using the equation
$$t=\sqrt{\frac{2h}{g}}$$.
This is simply the time taken for an object to fall a vertical distance ##h## and comes from re-arranging the one-dimensional motion equation
$$x=\frac{1}{2}at^{2}$$
and using ##h## for vertical distance and ##g## for acceleration.
 
I'm Awesome said:

Homework Statement


A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 6.60 m and D = 10.6 m, find H.

Homework Equations

The Attempt at a Solution



The solution was provided, this is a sample problem. I'm just very confused in how t was found to be sqrt(2h/g)

http://imgur.com/a/UuRNp

UuRNp
How are D, h and H defined in the question? The link to the solution works, but it looks like there is also a broken link, perhaps to the original question, or a diagram of it?
 

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