Quick Matrix Element Question using Hermitian Operator

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Discussion Overview

The discussion revolves around the properties of matrix elements involving Hermitian operators in quantum mechanics, specifically the expression <1|AB|2> and its relation to <2|BA|1>. Participants explore the conditions under which such transformations are valid, including considerations of compatibility of observables and the nature of the states involved.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant asks if <1|AB|2> can be rewritten as <2|BA|1>, suggesting that this could be done by taking the complex conjugate and noting that A and B are Hermitian operators.
  • Another participant emphasizes the need to include complex conjugation in the transformation, stating that <1|AB|2> = <2|BA|1>^*.
  • Several participants note that the transformation is only valid if A and B are compatible observables and if |1> and |2> are basis vectors of those observables.
  • A participant introduces a specific context involving a harmonic oscillator, expressing a desire to prove a relation between matrix elements of momentum and position operators, indicating a more complex problem than initially presented.
  • Another participant acknowledges that the general claim about the transformation holds for arbitrary state vectors, but reiterates the conditions necessary for the original question.

Areas of Agreement / Disagreement

Participants generally agree on the necessity of compatibility of observables and the conditions under which the matrix element transformation is valid. However, there is no consensus on the implications of these conditions for the specific problem presented by the original poster, leading to multiple competing views on the validity of the transformation.

Contextual Notes

The discussion highlights limitations regarding the assumptions about the compatibility of observables and the specific nature of the states involved, which are not fully resolved within the thread.

starryskiesx
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Hi there,

This should be very simple...

If I have a state <1|AB|2> where A and B are Hermitian operators, can I rewrite this as <2|BA|1> ?

That would be, taking the complex conjugate of the matrix element and saying that A*=A and B*=B.

Thank you!
 
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Well, you need to remember to include the complex conjugation:

##\langle 1 | A B | 2 \rangle^* = \langle 2 | B^\dagger A^\dagger | 1 \rangle = \langle 2 | B A | 1 \rangle##

so ##\langle 1 | A B | 2 \rangle = \langle 2 | B A | 1 \rangle^*##
 
The_Duck said:
Well, you need to remember to include the complex conjugation:

##\langle 1 | A B | 2 \rangle^* = \langle 2 | B^\dagger A^\dagger | 1 \rangle = \langle 2 | B A | 1 \rangle##

so ##\langle 1 | A B | 2 \rangle = \langle 2 | B A | 1 \rangle^*##

Great, thank you for the help
 
not necessarily, you need to also consider that this is only true if A and B are compatible observables, and it is only a matrix element if |1> and |2> are basis vectors of those same compatible observables.
 
raymo39 said:
not necessarily, you need to also consider that this is only true if A and B are compatible observables, and it is only a matrix element if |1> and |2> are basis vectors of those same compatible observables.

So it appears I have a bigger problem!

|1> and |2> are eigenstates of the hamiltonian, my system is that of a harmonic oscillator. What I'm trying to prove is that <1|P|2> = -imw<1|X|2>, starting with the matrix element [P,H] where H is the hamiltonian. I thought I could do this just by swapping eigenstates so now I'm more stuck :)

So far I've tried two methods, one involving writing H = T + V for the harmonic oscillator and finding the commutation relation and the other working with H|1> = E1|1> etc.

Any suggestions?
 
raymo39 said:
not necessarily, you need to also consider that this is only true if A and B are compatible observables, and it is only a matrix element if |1> and |2> are basis vectors of those same compatible observables.
What The Duck did holds in general, for arbitrary state vectors |1> and |2>.
 
Fredrik said:
What The Duck did holds in general, for arbitrary state vectors |1> and |2>.

I agree, my post was in reply to the original poster. Guess i was late to the party
 

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