Quick one: \varphi{(p)}- \varphi{(p-1)}= [\varphi{(\varphi{(p)})}]^3

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Thread starter al-mahed
Start date Jan 30, 2011

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al-mahed

Thread starter
Jan 30, 2011

find solutions where a) p is a prime; b) p is composite;

[tex]\varphi{(p)}- \varphi{(p-1)}= [\varphi{(\varphi{(p)})}]^3[/tex]

ps: it is not homework

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robert Ihnot

Jan 30, 2011

How about 3? phi(3)=2, phi(2)=1.

al-mahed

Jan 30, 2011

robert Ihnot said:

How about 3? phi(3)=2, phi(2)=1.

yes, is it the only one?

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Quick one: \varphi{(p)}- \varphi{(p-1)}= [\varphi{(\varphi{(p)})}]^3

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