Quick one: \varphi{(p)}- \varphi{(p-1)}= [\varphi{(\varphi{(p)})}]^3

  • Thread starter al-mahed
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  • #1
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find solutions where a) p is a prime; b) p is composite;

[tex]\varphi{(p)}- \varphi{(p-1)}= [\varphi{(\varphi{(p)})}]^3[/tex]

ps: it is not homework
 

Answers and Replies

  • #2
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How about 3? phi(3)=2, phi(2)=1.
 
  • #3
261
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How about 3? phi(3)=2, phi(2)=1.

yes, is it the only one?
 

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