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## Homework Statement

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. You find the arrow stuck in the ground 57.0m away, making a 2.00° angle with the ground.

vix = ?m/s

vfx = vix

viy = 0

vfy = ?m/s

dx = 57.0m

dy = ?

ax = 0

ay = -9.8m/s^2

dΘ = -2.00°

t = ?

## Homework Equations

d = (vi)(t) + (1/2)(a)(t^2)

vf^2 = (vi^2) + (2)(a)(d)

vf = vi + (a)(t)

d = ((vi + vf)/2)(t)

## The Attempt at a Solution

dΘ = -2.00°

ay = -9.8m/s^2

ω = angular velocity

α = angular acceleration

dΘ = (ωi)(t) + (1/2)(α)(t^2)

dx = (vix)(t) + (1/2)(ax)(t^2)

dx = (vix)(t)

(dx)/(vix) = t

dΘ = (ωi)(dx)/(vix) + (1/2)(α)(((dx)/(vix))^2)

dΘ = (1/2)(α)(((dx)/(vix))^2)

Well, this is as far as I know how to take it.

Any help is appreciated! Thanks in advance.