MHB Quick question about continuous mapping

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When f maps E into a metric space Y: (E is subset of metric space X)
Is it eqivalent to say that f is a continuous mapping and that for a subset E of X, to say that for every p element of E, f is continuous at p.?

thank you
 
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Yes. To say that a function (or mapping) is continuous is the same as saying that it is continuous at each point of its domain.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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