Quick question about Differential Equations.

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Discussion Overview

The discussion revolves around the derivation of an expression from a differential equation, specifically the transformation of the equation dy/dx = -x/2y into an integral form. Participants explore the steps involved in integrating both sides and the reasoning behind the resulting expressions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Ozone expresses confusion about how the term (y^2/2) is derived from the integral of y dy, suggesting it should simply be y.
  • Another participant clarifies that the integral of y dy is indeed (1/2)y^2 + c, paralleling the integration of (-x/2) dx which results in -(1/4)x^2 + c.
  • Further contributions introduce multivariable calculus concepts, suggesting a method involving level curves and partial derivatives to explain the derivation of the expression.
  • Participants note that constants of integration can differ and should not be assumed equal across different integrals.

Areas of Agreement / Disagreement

There is no consensus on the clarity of the derivation process, as Ozone remains uncertain about the transformation. While some participants provide explanations, the discussion reflects differing levels of understanding and interpretation of the integration steps.

Contextual Notes

Some assumptions about the integration process and the treatment of constants of integration are not fully resolved, leading to potential confusion regarding the derivation steps.

ozone
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I was working on a simple differential problem which caused me some confusion

original eq =

dy/dx = -x/2y

which can easily be altered into

y dy = (-x/2) dx

This finally transforms into (after antiderivatives are determined)

(y^2/2) = -(x^2/4) + c

While I can see that this logically is equivallent to the problem above I just don't see how the answer was derived. The x side of the equation makes perfect sense to me, but what I can't tell is how the y was derived to be (y^2/2). In my mind it should have just been y...

That aside I can see that the transformation is logical, but I can't figure out how it was derived.

Thanks,
Ozone.
 
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I don't see how you could say that! You say you see how [itex](x/2) dx[/itex] gives [itex]x^2/4+ c[/itex], I presume by recognizing that
[tex]\frac{1}{2}\int xdx= \frac{1}{2}\left(\frac{1}{2}x^2\right)+ c= \frac{x^2}{4}+ c[/tex]

Welll, the left side is not different:
[tex]\int y dy= \frac{1}{2}y^2+ c[/tex]

[tex]\int y dy= \frac{1}{2}\int x dx[/tex]
[tex]\frac{1}{2} y^2+ c_1= \frac{1}{4} x^2+ c_2[/tex]

I have written the two constants differently because there is no reason to think they have to be the same. Now subtract [itex]c_1[/itex] from both sides:
[tex]\frac{1}{2}y^2= \frac{1}{4}x^2+ (c_2- c_1)= \frac{1}{4}x^2+ c[/tex]
where "c" is just [itex]c_2- c_1[/itex].
 
Thanks hallsofivy this is exactly what I was looking for. Also I will be sure to use the forums coding next time :). (I responded to your other post after I made this post).
 
ozone said:
I was working on a simple differential problem which caused me some confusion

original eq =

dy/dx = -x/2y

which can easily be altered into

y dy = (-x/2) dx

This finally transforms into (after antiderivatives are determined)

(y^2/2) = -(x^2/4) + c

While I can see that this logically is equivallent to the problem above I just don't see how the answer was derived. The x side of the equation makes perfect sense to me, but what I can't tell is how the y was derived to be (y^2/2). In my mind it should have just been y...

That aside I can see that the transformation is logical, but I can't figure out how it was derived.

Thanks,
Ozone.

Set F(x,y)≡-x/2y then 0=dF=(∂F/∂x)dx+(∂F/∂y)dy and, -(∂F/∂x)/(∂F/∂y)=dy/dx. Reversing the steps should answer your question.
 
matphysik said:
Set F(x,y)≡-x/2y then 0=dF=(∂F/∂x)dx+(∂F/∂y)dy and, -(∂F/∂x)/(∂F/∂y)=dy/dx. Reversing the steps should answer your question.


I was not able to correct my rough work above, so i shall do it now. You (`ozone`) say that, "I can't figure out how it was DERIVED".

The `derivation` follows from simple multivariable calculus. Given dy/dx=-x/2y, rewrite it as 2ydy+xdx=0. Next, introduce F∈C¹(ℝ²) and set F(x,y)=constant (level curves), so that 0=dF=∂F/∂ydy+∂F/∂xdx.

Identify ∂F/∂y=2y (*), and ∂F/∂x=x (**). From (*), F(x,y)=y²+c₁(x) and from (**), F(x,y)=½x²+c₂(y). The obvious choice is, F(x,y)=½x²+y²+constant.
 

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