Quick Question About Photon Entering Atom

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SUMMARY

A photon must possess energy that exactly matches the difference between the atom's energy levels for absorption to occur. In the example provided, a photon with an energy of 5.86 eV cannot be absorbed by an atom transitioning from the ground state to E2 (5.74 eV) or E3 (5.96 eV). However, if the excess energy from the photon can be utilized in other processes, such as molecular vibrations, absorption may still occur. This principle underlies phenomena like fluorescence, Raman scattering, and Stokes and anti-Stokes shifts.

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Homework Statement


A photon enters an atom in the ground state. I have the energies to get to the next level.

My question is, does the photon have to be the exact energy to get to the next level before it is absorbed, or can the atom absorb it and go up those few levels and.. sort of store the extra energy until it either goes back to ground state and emits the photon or moves up again?

Example: A photon is entering that has an energy of 5.86 eV
E3 ----------- 5.96eV

E2 ----------- 5.74eV

Ground state -- 0 eV

Can the photon be absorbed, or would it have to be either 5.74 eV or 5.96 eV to be absorbed?
*Note, those numbers were made up and probably violate many laws of physics. :)
 
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No for the photon to be absorbed, the change in the energy levels must be the same as the energy the photon possesses.
 
If the excess energy can go into something else, like molecular vibrations, then it is possible that it could get absorbed. This would be the idea behind fluorescence, Raman scattering, Stokes and anti-Stokes shifts.
 

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