Quick question. How do you change the bounds of integration if using sec?

[randoreds]

And in general, always been bad at it.

If original bounds are ∫pi/3 to 0 and I am changing the bounds because I'm U-substituting.
My subtitution is u=secx

so is it when cos = pi/3 and 0 or am I wrong?
so the new bound would be from pi/2 to pi/3..?

 

[Mentallic]

the lower bound is x=\pi/3 right? And u=\sec(x) so the lower bound after the u-substitution will be u=\sec(\pi/3) and similarly the upper bound will be u=\sec(0)

 

[marvincwl]

just plug in the limits to the substitutition.

but usually you do not substitute a sec function, usually you would substitute a simpler function.

gd luck.

 

[randoreds]

the lower bound is x=\pi/3 right? And u=\sec(x) so the lower bound after the u-substitution will be u=\sec(\pi/3) and similarly the upper bound will be u=\sec(0)

No the upper bound is pi/3 the lower bound is zero(the number on the bottom of the integral sign is zero). the equation is ∫ dx/ (x^2 times sqrt(4-x^2))
So you would have to use trig and U substitution( I think)

with trig sub I got 1/4 ∫csc^2theta

so you got to change the bounds. Before you plug anything in.
u = sec(pi/3) My question was more how do I know what that is. because you can easily find sin, cos with unit circle. but I'm confused how to do it with sec and csc.

because I have no idea when sec = pi/3 and don't really remember how to figure it out ; /

because once you change the limits you can just integrate it. which would lead to -1/4 cot

then you could just plug in those values and find the answer

 

[Mentallic]

No the upper bound is pi/3 the lower bound is zero(the number on the bottom of the integral sign is zero). the equation is ∫ dx/ (x^2 times sqrt(4-x^2))
So you would have to use trig and U substitution( I think)

So with that problem, what did you make your U-sub?

u = sec(pi/3) My question was more how do I know what that is. because you can easily find sin, cos with unit circle. but I'm confused how to do it with sec and csc.

\sec(x)=\frac{1}{\cos(x)}

\csc(x)=\frac{1}{\sin(x)}

\cot(x)=\frac{1}{\tan(x)}

So then what is \sec(\pi/3) ?

because I have no idea when sec = pi/3 and don't really remember how to figure it out ; /

You're not looking for when "sec" = pi/3, you're looking for sec(pi/3).

because once you change the limits you can just integrate it. which would lead to -1/4 cot

then you could just plug in those values and find the answer

So you were fine with finding specific values of cot(x)?