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Quick SUVAT check

  1. Feb 2, 2013 #1
    I would just like someone to give a quick check to part b) of this question, just to make sure I have fully grasped the concept.

    A t=0s, particle P is fired vertically upwards with speed 17.64ms-1.When P reaches its maximum height, particle Q is fired vertically upwards with a speed 25ms-1. Both particles are fired from ground level.

    a) find the time between the two particles being fired.
    Ans:1.8s

    b) Find the length of the time after P is fired before the two particles become level.

    So I start with the SUVAT equation:

    S=Sp, U=17.64, V=0, T=T
    S=Sq, U=25, V=N/A, T=T-1.8

    I then use the equation [itex]S=ut+\frac{1}{2}at^2[/itex]

    I would the set Sp=Sq, and solve simultaneously.

    My point I would like to touch on is the t part. I set T=T because I do not know the total time take for the ball to reach maximum height; correct? T=T-1.8, because once again I do not know 1. the time taken for the ball to reach max height 2. - 1.8 because it was fired 1.8s later than the first.

    I did end up with the right ans which is t=2.44s. But just want to makes sure I have the right intuition behind the question.

    Big thanks in advance.
     
  2. jcsd
  3. Feb 2, 2013 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Yes you do. Good job.
     
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