R-parity and conservation of angular momentum

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The discussion centers on the conservation of angular momentum in processes involving R-parity and supersymmetric particles. It highlights that angular momentum conservation is similar to standard model (SM) processes, where initial and final states can have various total angular momentum values. The example of gluon interactions producing quark-antiquark pairs is used to illustrate this principle. The conversation also addresses the conditions under which reverse reactions are allowed, clarifying that R-parity conservation applies to particle-antiparticle annihilation. Overall, the conservation laws remain consistent across both SM and MSSM frameworks.
Ken41
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Assuming R-pairity and thus the creation/destruction of supersymmetric particles happens in pairs,
how is angular momentum conserved when a particle and its supersymmetric partner have different spin by 1/2?
 
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It depends on the process, but angular momentum will be conserved in ways that are already familiar from SM processes. For example, in the SM, we can have processes like ##gg\rightarrow q \bar{q} ##. At tree-level, there is a diagram

##g## ^^^^^^^^^^^^^^^^---------------------- ##q##
##\hspace{3.65cm}## |
##\hspace{3.65cm}## |
##\hspace{3.65cm}## |
##g## ^^^^^^^^^^^^^^^^---------------------- ##\bar{q}##

Angular momentum is conserved because the initial state can have ##J = 0,1,2,\ldots## and so can the final state.

In the MSSM, the same diagram can describe gluino production ##gg\rightarrow \tilde{g} \bar{\tilde{g}}##. It is also easy to add additional vertices to produce a 1-loop diagram with squarks or a squark + ##q\bar{q}## in the final state
 
Thanks for responding! Is it obvious why in your example, gg→g̃ barg̃ , ( where NN->SS) , the reverse reaction (SS->NN) would not be allowed? The R- parity would not change, so CPT stays the same...
 
Ken41 said:
Thanks for responding! Is it obvious why in your example, gg→g̃ barg̃ , ( where NN->SS) , the reverse reaction (SS->NN) would not be allowed? The R- parity would not change, so CPT stays the same...

The reverse reaction would be allowed. The R-parity of ##\tilde{g}## is ##-1##, but the R-partity is multiplicative, so for a system of two of them it is ##1##. In general, R-parity is conserved by particle-antiparticle annihilation for all SUSY particles.
 
More generally, any Feynman diagram's truth or falsity is never changed by rotating the diagram.
 
Ken41 said:
Assuming R-pairity and thus the creation/destruction of supersymmetric particles happens in pairs,
how is angular momentum conserved when a particle and its supersymmetric partner have different spin by 1/2?

Do you know this document: "mT2: the truth behind the glamour", arXiv:hep-ph/0304226v1, 23 April 2003? Perhaps you might be interested by it.
 
"Supernovae evidence for foundational change to cosmological models" https://arxiv.org/pdf/2412.15143 The paper claims: We compare the standard homogeneous cosmological model, i.e., spatially flat ΛCDM, and the timescape cosmology which invokes backreaction of inhomogeneities. Timescape, while statistically homogeneous and isotropic, departs from average Friedmann-Lemaître-Robertson-Walker evolution, and replaces dark energy by kinetic gravitational energy and its gradients, in explaining...

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