Radial component of del^2 in spherical coordinates? (again)

Click For Summary
SUMMARY

The discussion centers on the radial component of the Laplacian operator (del^2) in spherical coordinates, particularly in the context of a 3D isotropic harmonic oscillator. The correct expression for the radial part of del^2 is given by the formula 1/r^2 * d/dr(r^2 * d/dr), which simplifies to ∂^2f/∂r^2 + 2/r * ∂f/∂r. The confusion arises from the misunderstanding of the terms involved, specifically regarding the application of the product rule in differentiation. The reference to HyperPhysics and Zetilli's appendix B in quantum mechanics provides additional context for understanding these concepts.

PREREQUISITES
  • Understanding of spherical coordinates in mathematics
  • Familiarity with the Laplacian operator in vector calculus
  • Knowledge of differentiation techniques, including the product rule
  • Basic concepts of quantum mechanics, particularly isotropic harmonic oscillators
NEXT STEPS
  • Study the derivation of the Laplacian in spherical coordinates
  • Learn about the application of the product rule in calculus
  • Explore quantum mechanics concepts related to isotropic harmonic oscillators
  • Review resources on vector calculus, focusing on the Laplacian operator
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics and mathematical methods in physics, will benefit from this discussion. It is especially relevant for those tackling problems involving spherical coordinates and the Laplacian operator.

philip041
Messages
104
Reaction score
0
I'm doing a question on a 3D isotropic harmonic oscillator. At one point I need to find write the radial component of del^2.

Lecturer has written

<br /> <br /> \frac{1}{r^{2}} \frac{d}{dr} \left( r^{2} \frac{d}{dr} \right)<br /> <br />

where the del^2 used to be in the set of equations.

Am I correct in saying the radial part of in spherical polar coordinates is just dr. Then del^2 would be dr^2? Well I'm not?

I had a look at http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html but it didn't explain anything more for me.

PS. I asked this question earlier but internet broke, (thanks virgin media), and I don't understand the answer given... https://www.physicsforums.com/showthread.php?p=2006618#post2006618
 
Physics news on Phys.org
philip041 said:
I'm doing a question on a 3D isotropic harmonic oscillator. At one point I need to find write the radial component of del^2.

Lecturer has written

<br /> <br /> \frac{1}{r^{2}} \frac{d}{dr} \left( r^{2} \frac{d}{dr} \right)<br /> <br />

where the del^2 used to be in the set of equations.

Am I correct in saying the radial part of in spherical polar coordinates is just dr. Then del^2 would be dr^2? Well I'm not?

I had a look at http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html but it didn't explain anything more for me.

Hi philip041! :smile:

(have a theta: θ and a phi: φ and a curly d: ∂ :wink:)

isotropic means dθ = dφ = 0

so in http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html at http://hyperphysics.phy-astr.gsu.edu/hbase/lapl.html#c2, the only non-zero terms in the last line are ∂2f/∂r2 + 2/r ∂f/∂r,

which is the same as 1/r2 d/dr(r2d/dr) :smile:
 
Last edited by a moderator:
Thanks,

With ∂^2f/∂r^2 + 2/r ∂f/∂r how come it doesn't go to ∂^2/∂r^2 -1/r^2?

Sorry I don't understand how you get to that final line you wrote.
 
product rule

philip041 said:
With ∂^2f/∂r^2 + 2/r ∂f/∂r how come it doesn't go to ∂^2/∂r^2 -1/r^2?

uhhh? how did you get -1/r^2? :confused:

Hint: use the product rule to find d/dr(r2df/dr) :smile:
 
sweet. i also found an explanation of this in zetilli appendix b of quantum mechanics if anyone should ever search for this thread...
 

Similar threads

  • · Replies 46 ·
2
Replies
46
Views
5K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
6
Views
4K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 8 ·
Replies
8
Views
688
  • · Replies 3 ·
Replies
3
Views
6K