Radial postion - momentum uncertain for 2s Hydrogen

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SUMMARY

The discussion focuses on calculating the uncertainty in position and momentum for a Hydrogen atom in the 2s state. The wave function is given by ψ(r) = (1/2√π)(1/2a)^(3/2)(2 - (r/a))e^(-r/2a), where 'a' represents the Bohr radius. The participant successfully calculated the average position = 6a but struggled with determining and

. They proposed that

could be zero due to the spherical symmetry of the 2s state, but this was confirmed to be incorrect.

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TheRascalKing
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Homework Statement


I'm trying to calculate delta r * delta p for the Hydrogen atom in the 2s state

Homework Equations


ψ(r) = (1/ 2√π) (1 / 2a)^(3/2) (2 - (r/a)) e^(-r/2a)
where a is the bohr radius

The Attempt at a Solution


I figured out that <r> = 6a, but I'm at a loss as to how to figure out <r2> or <p>.

Using E = (-ke2 / 2a)(1/n2), and p2 = 2mE, i found <p2> = (m/2)(-ke2 / 2a), but I am not 100% sure this is right

EDIT: would <p> = 0 since Hydrogen 2s is spherically symmetric?
 
Last edited:
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TheRascalKing said:
I figured out that <r> = 6a, but I'm at a loss as to how to figure out <r2> or <p>.
How did you calculate ##\langle r \rangle##?


TheRascalKing said:
Using E = (-ke2 / 2a)(1/n2), and p2 = 2mE, i found <p2> = (m/2)(-ke2 / 2a), but I am not 100% sure this is right
What is ##k##?

TheRascalKing said:
EDIT: would <p> = 0 since Hydrogen 2s is spherically symmetric?
No.
 

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