Radiation Dose Rate from 60Co γ-Ray Source

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Homework Help Overview

The discussion revolves around calculating the radiation dose rate from a 60Co γ-ray source, specifically focusing on the dose received by individuals standing at a distance of 3 meters from the source. The problem involves understanding the contributions of both β particles and γ rays emitted during radioactive decay.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the β particle's range and its ability to reach individuals at a distance of 3 meters. Questions arise regarding the appropriate calculations for radiation flux and dose rate, with some suggesting the use of a point source model for the radiation distribution.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions made regarding particle behavior and the application of formulas. Some guidance has been offered regarding the calculation of radiation per area and the potential need for additional conversions to determine the dose rate for humans. There is an acknowledgment of the complexity of the question and the need for clarity in its wording.

Contextual Notes

Participants note that the question may be poorly worded and suggest seeking clarification from an instructor. There is also discussion about the limitations of the inverse square law in this context, indicating potential constraints in the problem setup.

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Homework Statement


Some people are standing at a distance of 3 m from an unshielded 60Co γ-ray source of activity
10^9 Bq. What radiation dose rate are they receiving? (Each disintegration of 60Co produces a
β particle of 0.3 MeV maximum energy with a range 0.8 m in air, and two γ rays, one of 1.2 MeV and one of 1.3 MeV, in quick cascade).


Homework Equations



dDose/dt = AE/r^2

A = activity
E = energy of photons
r = distance from source


The Attempt at a Solution



I'm at a bit of a loose end with this question as I've not been given any guidance - perhaps someone could suggest a relevant website to explain?
Due to the Beta particle traveling only 0.8m does this mean it doesn't reach the people standing 3m away? or does it decay into other particles?
Do i at some point calculate the flux of the rays? as i put the r^2 term in as i assumed it to be like a point source and diverging away (thus a 1/r^2 relation)

Thanks for any help and guidance on this question!
 
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Due to the Beta particle traveling only 0.8m does this mean it doesn't reach the people standing 3m away?
Right. An electron is an elementary particle, it cannot decay. It can produce Bremsstrahlung (photons), but that can be neglected I think - even if its total energy would be converted to Bremsstrahlung, 0.3 MeV << (1.2 MeV + 1.3 MeV).

as i put the r^2 term in as i assumed it to be like a point source and diverging away (thus a 1/r^2 relation)
That is fine for the radiation per area. You might need some additional conversion to get a radiation dose rate for those humans.
 
Ok... so do i just multiply it by the approximate area of a human?

I would have Radiation/area * area(of human) = radiation dose/per time(comes from the activity)
 
If humans absorb every photon which hits them, right. As an upper estimate, this should be fine.
 
This is a poorly worded question and you should tak your instructor (or the editor of the book) to task. The formula is (usually) the exposure rate, not the dose rate since not all gammas that pass through the body will be absorbed completely. In addition, the inverse square law applies only to point particles or geometries that approximate point particles.
 

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