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Radicals-> Exponential equations

  1. Mar 3, 2007 #1
    how would I take the cube root of the square root of 2 as an exponential equation? the square root of 2 is 21/2 but I dont know what to do with the cube root.
    Last edited: Mar 3, 2007
  2. jcsd
  3. Mar 3, 2007 #2


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    The cubed root of x is x1/3. So, your expression for the cubed root of the square root of 2 is [tex](2^{\frac{1}{2}})^{\frac{1}{3}}[/tex]. Can you simplify this?
  4. Mar 3, 2007 #3
    well Id have to simplify it, because im supposed to turn the new simplified exponent to a radical
    Last edited: Mar 3, 2007
  5. Mar 3, 2007 #4


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    Was that an answer to Cristo's question?? He asked do you know HOW to simplify it.
  6. Mar 3, 2007 #5
    oh, no i dont know how
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