how would I take the cube root of the square root of 2 as an exponential equation? the square root of 2 is 21/2 but I don't know what to do with the cube root.
The cubed root of x is x1/3. So, your expression for the cubed root of the square root of 2 is [tex](2^{\frac{1}{2}})^{\frac{1}{3}}[/tex]. Can you simplify this?
#3
rock4christ
34
0
well Id have to simplify it, because I am supposed to turn the new simplified exponent to a radical