Radio waves: constructive and destructive interference 1-dimension

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Homework Help Overview

The discussion revolves around the interference of radio waves emitted from two coherent sources, A and B, which are 5.00 m apart, each with a wavelength of 6.00 m. Participants are exploring conditions for constructive and destructive interference at various points along the line connecting the two sources, including scenarios where the sources differ in phase by 90 degrees.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of formulas for constructive and destructive interference, questioning the phase constant and how to account for the distance between the sources. There are attempts to calculate specific distances for interference conditions, with some participants expressing uncertainty about their results and the formulas used.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning the validity of their approaches. Some have provided specific distances for constructive and destructive interference, while others are seeking clarification on the correct application of formulas and the implications of the phase difference.

Contextual Notes

Participants are navigating the constraints of the problem, including the fixed distance between the sources and the specified phase difference, which may affect their calculations and interpretations of interference conditions.

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Homework Statement



Two coherent sources of radio waves, A and B, are 5.00 m apart. Each source emits waves
with wavelength 6.00 m. Consider points only along the line connecting the two sources.
(a) At what distance from source A is there constructive interference between points A and
B?
(b) At what (two) distances from source A is there destructive interference between points
A and B?

Suppose the two sources differ in phase by 90 instead.
(c) At what point(s) between the two sources do we get constructive interference?
(d) What is the nearest point to source A, but on the other side from source B, where we
get destructive interference?


Homework Equations



constructive: m*2pi= 2pi delta x / wavelength + phase constant
destructive: (m+1/2) *2pi= 2pi delta x / wavelength + phase constant

The Attempt at a Solution



for parts a/b, i am using phase constant = 0.
i used 0,1,... for m, and plugged into the equation to solve for delta x.
2pi= 2pi delta x / 6m + 0
delta x= 0m, 6m then is 0m the only distance from a where there is constructive interference?

how do you take into account that the sources are 5m apart?

for parts c/d, i am using phase constant = 90
2pi= 2pi delta x / 6m + pi/2
delta x= 9/2 m, 21/2 m is 4.5 m the distance from a for constructive interference?

i am assuming there's something I'm missing since the hints from the problem suggest 1 answer to part a, 2 distances for part b, etc.
 
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Curious, that formula doesn't work BETWEEN the two sources where the solutions lie.
 
Is there a different formula to use for interference?
 
Between the sources, for part (a) it is
distance from A = distance from B
x = 5 - x
 
ok, so for part a, i found delta x equals 0, so i set that equal to 5 -2x = 0 and got x=2.5 m.

for part b, i got delta x= 3, so 5-2x=3, and x= 1m and 4m. is this correct?

for part c, i used 2pi= 2pi delta x / 6m + pi/2 and got x=.25m and x=4.75m.

for part d, would i use 2pi(m +1/2)= 2pi delta x / 6m + pi/2?
 
I'm sure you have a, b, and c.
I don't see any solutions for d. The A to B distance amounts to 300 degrees, so the waves will always be 300 + 90 or 300 - 90 degrees out of phase.
 
thanks. for part d, when m=1, 3pi= 2pi delta x/ lambda + pi/2
so delta x = 7.5 m.
I said this would be the answer since 7.5 m is greater than 5 so this would be the distance from source A.
 
I don't see how delta x can be anything other than 5.
 

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