Radious of the geosynchronous ORBIT

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The radius of a geosynchronous orbit is determined by the balance between gravitational and centripetal forces acting on the satellite. A satellite in this orbit must maintain a specific angular velocity to remain above a fixed point on Earth, which is influenced by the Earth's rotation period of approximately 24 hours. While the radius can vary, the crucial factor is ensuring the satellite's orbital speed matches the Earth's rotational speed. The gravitational force acting on the satellite is inversely proportional to the square of its distance from the Earth's center. Thus, while the radius can be adjusted, the satellite's ability to remain geosynchronous is fundamentally linked to its orbital dynamics.
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a)

What is the radius of the orbit of a communications relay satellite that always reamins above one point on the Earth's surface? Such an orbit is called a geosynchronous orbit.


- I could find this on google but what is an another way to solve this?


b) Can such a satellite be placed in geosynchronous orbit over ANY point on Earth's surface? WHY?
 
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You can find it out by calculating it really. Are you sure that is the only important point? Radius is simply the height from the centre of the Earth and you can have almost any radius you want. What is important is angular velocity.
(Hint: How long does it take fo the Earth to make 1 full rotation?)

b) Yes and no really. The point is not as important as the actual orbit itself.
 
We assume that the satellite is in a circular orbit. This means that it is experiencing a centripetal force F_C supplied by the gravitational attractive force F_G of the earth

F_C = F_G

the centripetal force is given by

F_C = m\frac{v^2}{r}

with the mass and orbital speed of the satellite. r is its distance from the centre of the earth. The gravitational attractive force is given by

F_G = G \frac{Mm}{r^2}
 
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