Radius/interval of convergence

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Homework Statement

[tex]\Sigma[/tex] n!(2x-1)[tex]^{}n[/tex]

from n=1 to infinity

Homework Equations



-ratio test

The Attempt at a Solution



lim n-> infinity | (n+1)!(2x-1)^(n+1) / n!(2x-1)^n |

lim n-> infinity | (n+1)(2x-1) |

|2x - 1| lim n-> infinity | (n+1) |

-1 < 2x -1 < 1

0 < 2x < 2
0 < x < 1
I know at this point I've done something pretty wrong. as my interval and radius doesn't match up with the back of the book. could use a push in the right direction, thanks.
 
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oh, I am not too sure what to do with it. i understand that the limit goes to infinity, UNLESS x = 1/2 in which case it goes to 0. how do i proceed knowing that?

nm, i should just stop there ;)

1/2 is the only value of x for which this will converge, so the interval of convergence is {1/2}. the radius is 0.
 
Last edited:
karadda said:
oh, I am not too sure what to do with it. i understand that the limit goes to infinity, UNLESS x = 1/2 in which case it goes to 0. how do i proceed knowing that?

nm, i should just stop there ;)

1/2 is the only value of x for which this will converge, so the interval of convergence is {1/2}. the radius is 0.

I couldn't have said it better myself.